片语

divisible criterion by 3被整除的判别

divisible criterion by or整除的判别

Rings Characterized by Divisible Modules可除模对环的刻画

divisible criterion by 11被整除的判别

divisible criterion by or or整除的判别

divisible criterion by被3整除的判别

英汉例句

• this value must be divisible by 2, because the system assumes that the bit values of a bitmap form an array that is word aligned.

  该值必须为偶数，因为系统规定位图位值队列以字对齐。

• all even numbers that are divisible by four are in group two.

  所有的偶数是可分四个是在第二组。

• even hundred fold grief is divisible by love.

  再大的悲伤也会被爱驱散。

• all years that are divisible by 4 should be leap years of 366 days, except those which coincide with the beginning of a century.

  除了世纪开始的年份外，所有被四整除的年份应是由366天构成的闰年。

• if is the smallest cubic number divisible by 810, find the value of .

  如果是可被810整除的最小立方数，求的值。

• all the rest of the even numbers not divisible by four are in group three.

  所有其余的偶数不能整除四个组三个。

• as a result, the body of the second if statement is executed when the value of the variable i is evenly divisible by 125.

  因此，当变量i的值能被125整除时执行第二个if语句体。

• that may be another reason why chinese interest rates are divisible by nine: it is seen as an auspicious number.

  这也许正是中国设定利率需被9除尽的另一原因：9被视为一个吉祥的数字。

• so the filter expression will result in a sequence of integers where each is less than 1,000 and divisible by 3 or 5.

  因此，这个过滤器表达式的结果是一个整数序列，其中每个整数都小于1，000且能被3或5整除。

• now, these three new variables may not be all divisible by 5 (otherwise their sum would be too).

  现在，这三个新的数值不可能全都被5整除（否则它们的和也要被5整除）。

• years that are divisible by 100 are not leap years, unless they「re also divisible by 400.

  发现可被100整除的年份不一定是闰年，除非它能被400整除。

• the first if statement evaluates true, because 5 isn」t evenly divisible by 25.

  第一个if语句计算为true，因为5不能被25整除。

• the julian calendar approximated the mean tropical year as 365.25 days and proposed 366-day leap years for every one divisible by four.

  儒略历将太阳年划为365.25天，闰年366天，每四年一次。

• thirteen is not divisible by any even number.

  很多人认为十三是个不吉利的数字。 。

• why can「t you access a 4 byte long variable in a single memory access on an unaligned address(i. e. not divisible by 4), as it」s the case with aligned addresses?

  为什么你不能访问一个4字节长的变量在未对齐地址（即不被4整除）一个内存访问，因为它与对齐地址的情况？

• but century years divisible by 400, like 2000, would be leap years.

  但能被400整除的世纪年2000年，则为闰年。

• a positive integer is a prime if and only if it is exactly divisible by two integers, 1 and itself.

  一个正整数，如果能被并且只能被1和它本身整除，那么这个数就是一个素数。

• but now the second if statement evaluates true because the variable i is evenly divisible by 125 (and the not operator turns the resulting 0 into a boolean true).

  但是第二个if语句计算为true，因为变量i 能被125整除（并且not运算符将结果0转换成布尔值true）。

• as all objects start on an 8 byte boundary, and the size is divisible by 8, the bottom 3 bits are not used for the size; we use them for flags to indicate different states of the object.

  因为所有对象都是从8字节边界开始，并且大小可以被8整除，所以底部的3位不用于表示大小；我们将其作为标志，用于表示对象的不同状态。

• as all objects start on an 8 byte boundary, and the size is divisible by 8, the bottom 3 bits are not used for the size;

  因为所有对象都是从8字节边界开始，并且大小可以被8整除，所以底部的3位不用于表示大小；

• 1900 was a leap year! it「s divisible by 4!

  1900是闰年！

• jane street capital: 「what is the smallest number divisible by 225 that consists of all 1s and 0s?」

  简街资本：能被225整除，只包含0和1的最小的数字是多少？

• many number systems are based on 12 because it」s divisible by the most numbers, and because you can count to 12 on one hand by using your thumb to count three knuckles on each of the other fingers.

  许多数字体系都是基于12的，因为12可以被多数数字约分，还因为你可以一只手仅靠大拇指，数每个指头的指节，就能数到12。

• a prime number is a number that is not exactly divisible by any other number.

  一个最初始的数目是不可能被其它数字分化的。

• remember that you execute the body of an if statement only if the expression is true, which for this expression happens when the variable i is not evenly divisible by 25.

  记住，您只在表达式为true时执行if语句体。该表达式在当变量i不能被25整除时计算为true。

• the number 91, however, is not prime because it is divisible by 7 and 13. write a predicate method isprime(n) that returns true if the integer n is prime, and false otherwise.

  91就不是质数，因为它能被7和13整除编写一个断言方法isprime（n），在n是质数时返回true，反之返回false。