英语释义

• a real number (a scalar) that is the product of two vectors

片语

the dot product标量积

sliding-dot product互相关亦称为滑动点积

Deriving Dot Product Algebraically用代数方法来继承点积

spectral dot product在基于谱向量点积

red dot product design大奖得主

Dot product protocol点积协议

dot t product点积

double dot product[数]

英汉例句

• it「s the dot product between the normal vector of a plane and the vector along the line.

  这是平面法向量,和沿直线向量的点积。

• the dot product and matrices. read chapter3 through3.7 and do exercises.

  点积和矩阵。阅读第三章至3.7以及做练习题。

• these two vectors are perpendicular exactly when their dot product is zero.

  当点乘的数量积为零时,这两个向量垂直。

• and since work is a dot product between force and the direction that it travels, neither the tension nor the normal force does any work.

  既然功是力和运动,路程的点积,不管是张力还是,法向力都不做功。

• and, in some cases, for example, if you know that the vector field is tangent to the curve or if a dot product is constant or things like that then that might actually give you a very easy answer.

  例如，在某些情况下，如果已知向量场与曲线相切,或者内积是一个常数等等,那么结果将会很简单。

• and that is if i keep this force constant for that short amount of time is the dot product times the velocity, because dr/dt is simply the velocity of that object.

  如果我在短时内,保持这恒力,是点积乘以速率，因为dr/dt就是,物体的速率。

• you can immediately see by looking at this-- - it」s easier to see than looking here-- 0 that the dot product can be larger than zero 0 it can be equal to zero 0 and it can be smaller than zero.

  通过这个公式你立刻可以得出-,这比上面公式快多了-,点积可以大于,可以等于,也可以小于。

• and i can rewrite this in vector form as the gradient dot product the amount by which the position vector has changed.

  可以把这些用向量形式重新写下来,就是梯度向量和位置改变量的点积。

• then the line integral of f dot n ds will be the line integral of dot product .

  那么f?nds的线积分,就是?的积分。

• and work is a dot product between force and the direction of motion, perpendicular to each other.

  压力和,运动方向的，数量积彼此垂直。

• and, if you want to find what goes in a given slot here, then you just look to its left and you look above it, and you do the dot product between these guys.

  如果你要找到,这个位置的数是什么，那你就往左,和往上看，然后用它们做点乘。

• we can just find the angle using dot product so, how would we do that?

  可以直接用点积来,找到这个角的大小，那么，怎么找呢？

• but now the power that i have to generate is the dot product between the force and the velocity.

  但现在我要产生的,功率是力和速度,间的标量积。

• if i take the dot product but now, what does it mean that the dot product between op and a is zero?

  如果我用op·a我就得到了,那么op和a的点积是0代表了什么呢？

• ok, so now if we have a dot product that's zero, that tells us that these two guys are perpendicular.

  所以我们现在有了一个点积为，这告诉我们两者是垂直的。

• if you do the dot product with i hat, you will get the first component 0 that will be x1. one times x1 plus zero, zero.

  如果你用i做点乘，你能得到第一个分量,那就是x1，1*x1+0

• once you have such a formula, you do the dot product with this vector field, which is not the same as that one.

  一旦你得到一个这样的计算式，你对向量场做点积，这和前面这个不一样。

• what we will do is just, at every point along the curve, the dot product between the vector field and the normal vector.

  我们要做的是，沿着曲线的每一点上，取向量场和法向量的点积。